Odpowiedzi

2009-11-12T14:53:15+01:00
A][8x+16]=32→8x=32-16→8x=16→x=2 b]3[2x-3]-20=4→6x-9-20=4→6x=4+9+20→6x=33→x=5,5 c][5-4x]≤6→ -4x≤ 6-5→ -4x≤1/:[-4]→x≥ [-¼] d][6x+4]<-2→6x<-2-4→6x< -6→d< [ -1]-pozdrawiam
2009-11-12T15:03:52+01:00
A\\)[8x+16]=32
8x=32-16
8x=16/8
x=2

b)3[2x-3]-20=4
6x-9-20=4
6x-29=4
6x=4+29
6x=33/6
x=5,5

c)[5-4x]≤6
-4x≤6-5
-4x≤1 / -4
x≥-¼

d)[6x+4]<-2
6x< -6/ 6
x< -1
2009-11-12T15:49:19+01:00
A.[8x+16]=32
8x = 16
x=2

b.3[2x-3]-20=4
6x-9-20=4
6x=33
2x=11
x=5,5

c.[5-4x]≤6
-4x≤1
x≥-0,25

d.[6x+4]<-2
6x<-6
x<-1


Pozdrawiam! :)