Odpowiedzi

2009-11-12T21:36:47+01:00
(2x-3)/(x+1)-1= x/(x-1) |-x/x+1
2x-3/x+1-1-x/x+1=0
2x-3-x-x/x+1=0
-4x-3/x+1=0
(i4x-3)(x+1)=0
-4x²+4x-3x+3=0
-4x²+x+3=0
Δ=1²-4*(-4)*3
Δ=1+48=49
√Δ=7

x₁=-1-7/2*(-4)=-8/-8=1
x₂=-1+7/-8=-3/4
2009-11-12T22:03:09+01:00
2 + 1 - 3 / x - 3 = 1 - 1/x
3 - 3/x -3 = 1 - 1/x / + 1/x
3 - 3/x - 3 + 1/x = 1 / -3
- 2/x = -2 / × x
-2 = -2x /÷ -2
0 = x