Odpowiedzi

2009-11-13T16:58:43+01:00
Oblicz objętość i pole powierzchni prostopadłościanu o wymiarach
a)a=6cm, b=3cm, c=9cm.
V=abc
V=6*3*9=162cm³
b)a=6dm, b=60cm=6dm c=4,2dm.
V=6*6*4,2=151,2dm³
c)a=2m, b=0,4m, c=2,8dm=0,28m
V=2*0,4*0,28=0,224m³.
2009-11-13T16:59:46+01:00
A) Pp=2*6*3
Pp=36

Pb=2*6*9+2*3*9
Pb=108+54
Pb=162

Pc=36+162
Pc=198 (cm2)

V=6*3*9
V=162(cm3)

B)Pp=60*60
Pp=3600cm2

Pb=4*60*42
Pb=10080cm2

Pc=10080+3600
Pc=13680cm2=136,8

V=60*60*42
V=151200cm3=151,2dm3

C)Pp=200*40
Pp=8000cm2

Pb=2*200*28+2*40*28
Pb=11200+2240
Pb=13440cm2=0,01344m2

V=200*40*28
V=224000cm3=0,224m3
2009-11-13T17:34:04+01:00

P= Pp + Pb
Pp = a*b
Pb = 2(a*c) + 2(b*c)

V = a*b*c

a) a=6cm
b= 3cm
c= 9cm

Pp = 6*3
Pp = 18cm²
Pb = 2(6*9) + 2(3*9)
Pb = 108 + 54
Pb = 162 cm²
Pc = 18cm² + 162 cm² = 180 cm²

V = 6*3*9
V = 162 cm³

b) a = 60cm
b = 60cm
c = 42 cm

Pp = 60 * 60
Pp = 3600 cm²
Pb = 4(60*42)
Pb = 100 80 cm²
Pc = 13680 cm²
V = 60*60*42 = 151 200 cm³

c) a= 2m
b= 0,4m
c= 0,28 m

Pp = 2*0,4
Pp = 0,8 m²
Pb = 2(2*0,28) + 2(0,4*0,28)
Pb = 1,12 + 0,23
Pb = 1, 35 m²
Pc = 0,8 + 1,35 = 2,15 m²
V = 2*0,4*0,28
V = 0,224m³