Odpowiedzi

2009-11-14T02:05:33+01:00
(X3+3x+1) *(4x3 -2x2+x-2) – (2x4+x3-x+6) = 4x6-2x5+x4-6x3+12x4-6x3+3x2-6x+4x3-2x2+x-2 – (2x4+x3-x+6) = 4x6-2x5+13x4-8x3+x2-5x-2 – 2x4-x3+x-6 = 4x6-2x5+11x4-9x3+x2-4x-8

gdzie np 4x6 oznacza 4x do potęgi 6