Odpowiedzi

2009-11-14T22:44:04+01:00
Sinα = 12/13

sin²α + cos²α = 1
cos²α= 1 - 144/169
cosα=5/13

tgα=sinα/cosα = 12/13 / 5/13 = 12/5
ctgα= 1/tgα = 5/12