Odpowiedzi

2009-11-16T14:44:57+01:00
Odp . v = 225000 km/s
t' = t*sqrt(1-b^2)
t'=0,25 h
t =1,00 h
c = 300000 km/s
b=v/c
t'=t*sqrt(1-v^2/c^2)
t'^2=t^2*(1-V^2/c^2)
t'^2=t^2 - t^2*v^2/c^2
t'^2 = (t^2*c^2 - t^2*v^2)/c^2
t'^2*c^2=t^2 *c^2 - t^2*v^2
t^2*V^2 = t^*c^2 - t'^2*c^2
V^2 = c^2(t^2-t'^2)/t^2 dla t=1
v=sqrt*(c^2*(t^2-t'^2))
v= 225000 km/sek