Odpowiedzi

2009-11-16T22:31:45+01:00
M Cu(OH)2= 64 + ( 16 + 1 )*2 = 98 g/mol
1 mol = 98 g/mol
5 moli = x
x= 5 * 98 = 490g.
2009-11-16T22:31:35+01:00
2009-11-16T22:33:11+01:00
5 moli Cu(OH)2

n=5 moli
MCu(OH)2= 98g/mol
m=?

n=m/M
m=n*M
m=5moli* 98g/mol
m=490g