Odpowiedzi

2009-11-18T18:22:58+01:00
-(x-2 xy)-(4x+xy)+(xy-z)=
-x+2xy-4x-xy+xy-z =
-5x-2xy-z

(x² + 2x +1) - (x² - 4x + 3)=
x²+2x+1-x²+4x-3=
6x-2

(2a+b) *c - (2ac-bc+1)=
2ac+bc - 2ac +bc-1=
2bc-1

5(x-z)+2(z-x)=
5x-5z+2z-2x=
3x-3z