Odpowiedzi

2009-11-18T19:34:36+01:00
X/(x+2)-3/(x-2) =
=x(x-2)/[(x+2)(x-2)]-3(x+2)/[(x-2)(x+2)] =
=[x²-2x-3x-6]/[(x-2)(x+2)] =(x²-5x-6)/(x²-4)
mam nadzieje ze o to chodzilo
2009-11-18T19:40:58+01:00
X/(x+2)-3/(x-2) =
=x(x-2)/[(x+2)(x-2)]-3(x+2)/[(x-2)(x+2)] =
=[x²-2x-3x-6]/[(x-2)(x+2)] =(x²-5x-6)/(x²-4)