Odpowiedzi

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2009-11-19T22:53:48+01:00
X + y = 20
x^2 + y^2 =208
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x = 20 - y
(20 - y)^2 + y^2 = 208
400 -40y +y^2 + y^2 = 208
2y^2 - 40y + 192 = 0 / 2
y^2 - 20y + 96 = 0
Δ = 400 - 4*96 = 400 - 384 = 16
√Δ = 4
y1 = [20 -4]/2 = 8
y2 = [20 + 4]/2 =12
x1 = 20 - 8 = 12
x2 = 20 -12 = 8
Odp. x = 12 , y = 8 lub x =8 , y =12
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