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2009-11-20T15:59:59+01:00
A)IACI=4 IABI=5
x²+4²=5² x=3
sinalfa=3/5 sinbeta=4/5
cosalfa=4/5 cosbeta=3/5
tgL=3/4 tgB=4/3
ctgL=4/3 ctgB=3/4
1 5 1
2009-11-20T16:07:55+01:00
A)sin BAC = 3/5 = 0,6
cos BAC =4/5 = 0,8
tg BAC =3/4 = 0,75
ctg BAC = 4/3
b) 7^2 + 7^2 = 49 +49 =2*49
AB = 7√2
sin BAC = 7/7√2 = 1/√2 = √2/2
cos BAC =√2/2
tg BAC = 1 oraz ctg BAC = 1
c)
BC^2 = 9 -8 =1 , BC = 1
sin BAC = 1/3
cos BAC =2√2/3
tg BAC = 1/2√2
ctg BAC = 2√2
d) AC^2 = 25*5 - 10^2 = 25
AC = 5
sin BAC =10/5√5 = 2/√5
cos BAC = 5/5√5 = 1/√5
tg BAC = 10/5 = 2
ctg BAC = 5/10 = 1/2
4 5 4