Odpowiedzi

2009-11-20T18:12:35+01:00
A) (x - 1)(x³ + x² + x + 1) = x ^ 4 + x³ + x² + x - x³ - x² - x - 1 = x ^ 4 - 1
b) (x + 1)(x³ - x² + x - 1) = x ^ 4 - x³ + x² - x + x³ - x² + x - 1 = x ^ 4 - 1

NIe było takie trudne
2009-11-20T19:27:31+01:00
A) (x-1)(x³+x²+x+1)

(x-1)(x³+x²+x+1)=
=(x-1)[x²(x+1)+(x+1)]=
=(x-1)[(x+1)(x²+1)]=
=(x²-1)(x²+1)=
=x⁴-1

b) (x + 1)(x³ - x² + x - 1)
(x + 1)(x³ - x² + x - 1)=
=(x+1)[x²(x-1)+(x-1)]=
=(x+1)[(x-1)(x²+1)]=
=(x²-1)(x²+1)=
=x⁴-1