Odpowiedzi

2009-11-21T15:54:05+01:00
Ca(OH)2=40g + 32g + 2g=74g
mr=40-do zawartosci procentowej wapnia
cp=40/74 x 100%
cp=4000/74%
cp=54 % wapnia

mr=32 do zawartosci procentowej tlenu
cp=32/74 * 100%
cp=3200/74%
cp=43% tlenu

mr-2
cp=2/74* 100%
cp=200/74 %
cp~3% wodoru
2009-11-21T16:01:36+01:00
Ca(OH)2 = 40u + 2*16u + 2u = 74u

%Ca= 40u*100%/74u = 54,054%
%O= 32u*100%/74u= 43,243%
%H= 2u*100%/74u= 2,703%