Odpowiedzi

2009-11-22T14:08:32+01:00
(1/3 x – 1/2 y)(6x-12y) – [3y- ( pierw. 2x)do kwadratu]do kwadratu + 3y do kwadratu= 2x²-4xy-3xy+6y²-(3y-2x)²+9y²=
=2x²-7xy+6y²-(9y²-12xy+4x²)+9y²=
=2x²-7xy+6y²-9y²+12xy-4x²+9y²=
=-2x²+5xy+6y²

-2x²+5xy+6y²= -2(0,03)²+5(0,03)(⅖) +6(⅖)²=
=-2 * 0,0009 + 0,06 + 24/25 = 0.0018 + 0.06+ 0.96 = 1,0218