Odpowiedzi

2009-11-22T15:54:18+01:00
A) [ (n+70) + (n+71) + (n+72) + (n+73) ] / 4 = [4n + 286] / 4 = n + 71,5

b) [ (n-2) + (n-1) + n + (n+1) ] / 4 = [4n - 2] / 4 = n - 0,5
42 4 42
2009-11-22T15:57:19+01:00
[(n+70)+(n+71)+(n+72)+(n+73)] : 4 = n+71.5


[(n-2) + (n-1) +( n) + (n+1)] :4 = n-0.5
13 4 13
2009-11-22T15:59:53+01:00
1)
[(n+70)+(n+71)+(n+72)+(n+73)]:4 = n+71.5
2)
[(n-2)+(n-1)+( n)+(n+1)]:4 = n-0.5
12 4 12