Odpowiedzi

2009-05-17T18:55:18+02:00
A. 2×2×2×2=16
b. 5×5×5=125
c. (-11)×(-11)=121
d. (-3)×(-3)×(-3)×(-3)=81
e. (-6)×(-6)×(-6)= - 216


a. (-2,1)×(-2,1)×(-2,1)= -9.261≈-9,27≈-9,3
b. 0,1×0,1×0,1×0,1×0,1×0,1×0,1×0,1×0,1=0,000000001 jeżeli tam jest (0,1) do potęgi 9 bo nie widze dokładnie jak do potęki 8 to jedno 0 mniej i tak dalej
2009-05-17T18:55:21+02:00
A) 2⁴ = 2*2*2*2 = 16
b) 5³ = 5*5*5 = 125
c) (-11)² = (-11)*(-11) = 121
d) (-3)⁴ = (-3)*(-3)*(-3)*(-3) = 81
e) (-6)³ = (-6)*(-6)*(-6) = -216

a) (-2,1)³ = (-2,1)*(-2,1)*(-2,1) = -9,261
b) (0,1)⁵ = (0,1)*(0,1)*(0,1)*(0,1)*(0,1) = 0,00001
2009-05-17T18:57:55+02:00
A/ 2⁴ = 2*2*2*2 = 16
b/ 5³ = 5*5*5 = 125
c/ (-11)² = (-11)*(-11) = 121
d/ (-3)³ = (-3)*(-3)*(-3) = -27
e/ (-6)³ = (-6)*(-6)*(-6) = -216




a/ (-2,1)³ = (-2,1)*(-2,1)*(-2,1) = -9,261
b/ (0,1)⁵ = (0,1)*(0,1)*(0,1)*(0,1)*(0,1) = 0,00001