Odpowiedzi

2009-05-18T16:11:35+02:00
Glukoza - C₆H₁₂O₆
Mgluzkoy=6*12u+12*1u+6*16u=180u

%C=72/180*100%=40%
%H=12/180*100%=6,66%
%O=100%-(6,66%+40%)=53,34%