Dokończ równania rekcji
1)C6 H13 COOH+.......--->CO2+..........
2)............+14 O2--->10CO2+............
3)CH3COOK+---H2O---->.........+.......
4)C2H5COOH+K------>..........+............
5)C17H35COOH+.........----->C17H35COONa+..........
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1

Odpowiedzi

2011-06-16T14:57:29+02:00

1)2C6 H13 COOH+19O2--->14CO2+14H2O
2)C9H19COOH+14 O2--->10CO2+10H2O
3)CH3COOK+---H2O---->CH3COO(-) + K(+)
4)2C2H5COOH+2K------>2C2H5COOK+H2
5)C17H35COOH+NaOH----->C17H35COONa+H2O