Odpowiedzi

  • Użytkownik Zadane
2009-05-18T19:53:28+02:00
X(x - 4) < 8
x² - 4x < 8
x² - 4x - 8 < 0

x² - 4x - 8 = 0
Δ = (-4)² - 4 * 1 * (-8) = 16 +32 = 48
√Δ = 4√3
x1 = 4 + 4√3 / 2 = 2 + 2√3
x2 = 2 - 2√3

x(x-4) < 8 dla x ∈ (2 - 2√3; 2 + 2√3)
2009-05-18T19:58:52+02:00
X(x-4)<8
2x-4x<8
-2x<8/:(-2)
x<-4
x=-2
2009-05-18T20:02:23+02:00