Odpowiedzi

2009-05-20T23:48:40+02:00
CH3COOH + CH3OH => CH3COOCH3 + H2O
M octanu etylu = 74g/mol

n= 220g/74g/mol
n=3mole

1mol CH3COOH - 1 mol CH3COOCH3
Xmoli ----------- 3mole

xmoli = 3mole
uwzględniamy wydajność
83% = 0,83 ( z matematyki:p)
3mole x 0,83 = 2,49mola CH3COOH
M CH3COOH = 60g/mol
m = 2,49mola x 60g/mol = 150g