Odpowiedzi

2009-11-25T20:09:42+01:00
W laczeniu rownoleglym
1/Rz = 1/R1 + 1/R2

1/Rz = 1/6 + 1/3
1/Rz = 1/2
Rz = 2 [Ω]
2009-11-25T20:10:13+01:00
2009-11-25T20:13:20+01:00
1/R = 1/R1 + 1/R2
1/R = 1/6 + 1/3
1/R = 1/6 + 2/6
1/R = 3/6Ω
R = 6Ω/3
R = 2Ω