2. OBLICZ:
a) (-3)²×[(-3/2)×(9/8)`` 9/8do potegi minus 1`` -2/9×(3/8)]
-------------------------------------------------------------------- =
√1⁹/₁₆ × 1/2

b)√1⁹/₁₆ × 2/3+(-3 ¹/₃):2
---------------------------- =
-2³ × 1/2
BARDZO PROSZE NIECH KTOS MI POMOZE!!!!PILNIEEEE NA JUTRO RANO!!! Z GORY DZIEKUJE

1

Odpowiedzi

  • Użytkownik Zadane
2009-05-22T00:16:38+02:00
(-3)²×[(-3/2)×(9/8)`` 9/8do potegi minus 1`` -2/9×(3/8)]
-------------------------------------------------------------------- =
√1⁹/₁₆ × 1/2

9*(-3/2*8/9-1/12) 9*(-4/3-1/12) 9*(-16/12-1/12) 9*(-17/12)
-------------------- = -------------- = ----------------- = ----------- =
√25/16*1/2 5/4*1/2 5/8 5/8

-51/4
------- = -51/4*8/5= -102/5 = -20 2/5= -20,4
5/8


b)√1⁹/₁₆ × 2/3+(-3 ¹/₃):2 √25/16*2/3+(-10/3*1/2)
---------------------------- = ---------------------------
-2³ × 1/2 -8*1/2

5/4*2/3-5/3 5/6-10/6
--------------- = ----------- = -4/6 * (-1/4) = 1/6
-4 -4