Odpowiedzi

2009-11-26T11:34:02+01:00
A1+a2+a3=15
a2=a1+r
a3=a1+2r
3a1+3r=15
a1+r=5 =a2
a1=a2−r= 5−r
a3=5+r

5−r+5=a1^
5+3=8=a2^
5+r+19=24+5=a3^

82=a1^2+a3^2
64=240+10r−24r−r2 r2+14r−176=0
√Δ=30
r=8 lub
r= −22