Odpowiedzi

2009-11-26T15:49:21+01:00
16-5y+x+2x+3y-18
3x-2y+16-18
3x1/3-2(-1/2)-2
1+1-2=0
2 5 2
2009-11-26T21:05:11+01:00
16-5y+x+2x+3y-18=-2-2y+3x=-2-⅔-1½=-2-4/6-1i3/6=-2i4/6-1i3/6=-4i1/6
1 5 1
2009-11-26T21:15:27+01:00
(16-5y+x) + (2x+3y-18)= -2-2y+3x

x = ⅓
y = -½


-2-2×(-½)+3×⅓ = -2 +1 +1 = 0
1 1 1