Odpowiedzi

2009-11-26T17:29:38+01:00
16-5y+x + 2x+3y-18 =
-2-2y+3x
podstawiamy liczby pod x i y

-2-2*(-1/2)+3*(1/3) =
-2+1+1 = 0

wartosc liczbowa wynosi 0
2009-11-26T17:33:23+01:00
16-5y+x+2x+3y-18=-2-2y+3x
-2-2×1/3+3×(-1/2)=-2-2/3+(-3/2)=-2-4/6-9/6=-2-13/6= -4 i 1/6
2009-11-26T20:46:16+01:00
(16-5y+x) + (2x+3y-18) = 16-5y+x+2x+3y-18 = -2-2y+3x

x = ⅓
y = -½

-2 - 2 × (-½) + 3 × ⅓ = -2 - (-1) + 1 = 0