Odpowiedzi

  • Użytkownik Zadane
2009-05-23T17:19:42+02:00
2x - 3 / x - 1 + 1 = 6x - x² - 6 / x - 1 /*(x-1)
2x - 3 + x - 1 = 6x - x² - 6
x² - 3x = -2
x² - 3x + 2 = 0

Δ = (-3)² - 4 * 1 * (2) = 9 - 8 = 1
x1 = (3 + 1) / 2 = 2
x2 = (3 - 1) / 2 = 1

x = 1 lub x = 2