Odpowiedzi

2009-11-27T16:18:48+01:00
(-2xy)²-(1-x²)(y²-1)+2xy =4x²y²-1y²-1-x²y²+x²+2xy=3x²y²-1y²-1+x²+2xy
5-(2√2x+√2+√8)(x-√8)=5-(2√2x+√2+2√2)(x-2√2)=5-(2√2x+3√2)(x-2√2)=
=5-2√2x²-4√4x+3√2-6√4=5-2√2x²-4√4x+3√2-6*2=5-2√2x²-4√4x+3√2-12=
=-7-2√2x²-4√4x+3√2