Odpowiedzi

2009-11-26T18:36:05+01:00
Zad.1
1) P4 + 5O2 ---> P4O10
2) P4O10 + 6H2O ---> 4H3PO4

Zad.2
H3PO4
mH = 1u 1u*3 = 3u
mP = 31u
mO = 16u 16u*4 = 64u

3u+31u+64u = 98u
98u --- 100%
31u --- x%

x=31*100/98
x=31,6 %
10 4 10
2009-11-26T18:38:25+01:00
1)P₄+5O₂→P₄O₁₀
P₄O₁₀+6H₂O→4H₃PO₄
2)m=3*1+31+16*4=98u
98u-100%
31u-x%
x=31,63
4 4 4