Odpowiedzi

2009-11-26T19:26:37+01:00
(5k+n)(k-2n)-k(4k+n)=
=5k² -10kn +kn-2n²-4k²-kn=
=k²-10kn-2n²


-(3c-2)(c-1)-c(c-2) =
= -(3c²-3c-2c+2)-c²+2c=
=-3c²+3c+2c-2-c²+2c=
= -4c²+7c-2

:)
1 5 1
2009-11-26T23:09:36+01:00
A)(5k+n)(k-2n)-k(4k+n)=
=5k² -10kn +kn-2n²-4k²-kn=
=k²-10kn-2n²

b)-(3c-2)(c-1)-c(c-2) =
= -(3c²-3c-2c+2)-c²+2c=
=-3c²+3c+2c-2-c²+2c=
= -4c²+7c-2
1 5 1