Odpowiedzi

2009-12-02T20:52:48+01:00
A) 4(y-3)-3(x+1)=4y-12-3x-3
4*2-12-3*4-3=8-12-12-3=-19
b) 3(2b+1)-4(a-2)=6b+3-4a+8
6*1+3-4*7+8=6+3-28+8=-11
c) 9(x-2y)-(5y-2x)+20y=9x-18y-5y+2x+20y=11x-3y
11*0,5-3*0,3=5,5-0,9=4,6
d) (5x+7y)-8(y+1)+3(x+y)=5x+7y-8y-8+3x+3y=8x+2y-8
8*1/2+2*1/4-8=4+1/2-8=-4,5