Odpowiedzi

2009-12-02T21:35:31+01:00
2Na + 2H2O -> 2NaOH + H2
2 mole sodu --- 1 mol naoh
1 mol sodu ---- 1 mol naoh
23g na -------- 40g
11,5g----- x

x=20g NaOH

z mole Na ----- 1 mol H2
46g Na --------- 2 g
11.5 g ------ x

x = 0.5 g
1 1 1
2009-12-02T21:41:50+01:00
Na + H₂O → NaOH + ½H₂

m(masa molowa) Na - 23g/mol
m NaOH - 23 + 16 + 1 = 40g/mol

z 23g Na powstaje 40g NaOH
z 11,5g Na powstaje xg NaOH

23 - 40
11,5 - x

x = 11,5 × 40 / 23 = 20

Powstanie 20g NaOH

mH = 1g/mol
23g Na - 1g H
11,5 Na - xg H

x = 0,5g

Powstanie 0,5g H