Odpowiedzi

2009-12-04T13:14:11+01:00
Y=sin^7(x^2+4x-5)=
y'=7 sin⁶(x²+4x-5)*cos(x²+4x-5)*(2x+4)

y=pierwiastek cos^3(4x-1)=
y'=[1/2√(cos³(4x-1)]*3cos²(4x-1)*(-sin(4x-1)*4