Odpowiedzi

2009-12-05T22:29:49+01:00
25⁹x=(5¹⁷-5¹⁶):(125²-25^⁻⁹/₂)
(5²)⁹x=5¹:[(5³)²-(5²)^₋⁹/₂]
5¹⁸x=5¹:[(5⁶)-(5⁻⁹)]/÷5¹⁸
x=5¹:[(5⁶)-(5⁻⁹)]*1/5¹⁸
x=5:[5(5⁵-5⁻¹⁰)]*1/5¹⁸
x=1:{[5⁵-5⁻¹⁰]*5¹⁸}
x=1:[5²³-5⁸]
x=1:[5⁸(5¹⁵-1)]
1 1 1
2009-12-06T00:53:21+01:00
25^9x= (5^17 - 5^16) : (125^2 - 25^-9/2)
* 25^-9/2 tj. 25 do potęgi -9/2
(5²)^9x = 5:[ (5³)²-(5²)^-9/2]* (5²)^-9/2
5^18x=5:(5⁶-5⁻⁹)*5⁻⁹
5^18x=5:( 5¹⁵:5⁹)*5⁻⁹
5^18x=5:5⁶*5⁻⁹
5^18x=5:5⁻³
5^18x=5⁴
18x=4
x=2/9
2 2 2