Odpowiedzi

2009-12-04T22:20:17+01:00
(x+2)² - (y-2)²= 3 +(x-3)² -y²
x²+4x+4-y²-4y+4=3+x²-6x+9-y²
4x+4-4y+4=3-6x+9
10x-4y=1

x-5y+3 *({2x+3} / 2) - ({1½+3y}/3) = 0
x-5y+3*((2x+3)*½)-((1½+3y)*1/3)=0
x-5y+3*(x+1.5)-(0,5+y)=0
x-5y+3x+4.5-0,5-y=0
4x-6y+4=0
4x-6y=-4

masz