Odpowiedzi

2009-12-06T14:35:54+01:00
Lim ((n^2+1)n!+1)/(2n+1)(n+1)!=lim(n!((n²+1)+1/n!))/(2n+1)n!(n+1))=
(1/n!=0,n! skracamy)=lim(n²+1)/(2n+1)(n+1)=lim(n²+1)/(2n²+3n+1)=
=lim(n²(1+1/n²))/n²(2+3/n+1/n²)=(n²skracamy,1/n²=0. 3/n=0)=
=lim1/2=1/2