Odpowiedzi

2009-12-06T20:30:41+01:00
A) (an)=(1-n)/(1+n)
(an+1)=(-n)/(n+2)

(an+1)-(an)=(-3n-6)/[(n+1)(n+2)]

b)(an)=n²-2n
(an+1)=n²+2n+1-2n=2=n²-1