Odpowiedzi

2009-12-06T21:22:28+01:00
2009-12-06T21:25:34+01:00
2x-3y=10
5x-5y=0
2x=10+3y/:2
x=5+1½y

5(5+1,5y)=0
25+17,5y=0
17,5y=-25
y=-1 ¹/₇
x=5+1½*(-1 ¹/₇)
x=3 ³/₇
y=-1 ¹/₇

Jest dobrze jezeli w drugim byl minus
2009-12-07T01:32:57+01:00
2x-3y =10/*5
5x+5y =0 /*3

10x -15y =50
15x+15y=0

25x=50 /25
x=2
15*2+15y=0
15y=-30/ 15
y=-2
1 5 1