Odpowiedzi

2009-03-30T14:22:57+02:00
Dane: Szukane:
m₁=1kg m₂=?
t₁=20°C
t₂=90°C
t₃=60°C
Cw=4200J/kg×°C

Rozw:
Q₁=Q₂
m₁×Cw×(t₃-t₁)=m₂×Cw×(t₂-t₃)
m₁×(t₃-t₁)=m₂×(t₂-t₃)
m₂=m₁×(t₃-t₁)/(t₂-t₃)
m₂=1kg×(60°C-20°C)/(90°C-60°C)
m₂=1kg×40°C/30°C
m₂=40kg°C/30°C=⁴/₃kg

Odp. Dolano ⁴/₃kg wody gorącej.
4 2 4
2009-03-30T14:27:27+02:00
Kalorymetria ilosc ciepla Q=mcT - masa cieplo wl. temp

m1=1kg
t1= 20*C
t2= 90*C
t3=60*C
OBL dm
m1c1t1+ dm*c1*t2=(m1+dm)*c1*t3
m1t1+dmt2=m1t3+dmt3
m1(t3-t1)=dm(t2-t3)

dm=m1(t3-t1)/(t2-t3)=1*40/30=4/3kg

Dolano 4/3kg wody