Odpowiedzi

2009-12-07T21:59:00+01:00
Dane
P1=60W
P2=40W
U=230V
Rr=?
Rs=?
P=U*I
prawo Ohma I=U/R stąd P=U²/R i R=U²/P
R1=230²/60=882Ω
R2=230²/40=1323Ω
Rr=R1*R2/(R1+R2)=882*1323/(882+1323)=529Ω
Rs=R1+R2=882+1323=2205Ω
2 3 2