Odpowiedzi

2009-12-09T14:08:07+01:00
CH3COOH + NaOH = CH3COONa + H2O

6 g ---------- x g
60 g --------- 40 g

x = 4 g
2009-12-09T14:15:54+01:00
CH3COOH + NaOH = CH3COONa + H2O
mCH3COOH = 60g
mNaOH = 40g
W jednym molu mamy 60g CH3COOH i 40g NaOH, tak więc układamy proporcję:

60 g CH3COOH ----- 6g
40g NaOH ------- xg

60x = 40g * 6g
60x = 240g / : 60
x = 4g
Potrzeba 4g NaOH
2009-12-09T16:25:28+01:00
CH3COOH + NaOH = CH3COONa + H2O

60g ------ 40g
6g ------ xg

x = 4 g

Odp. Potrzeba 4g NaOH.