Odpowiedzi

2009-12-08T17:56:39+01:00
(√3x - 2)(√3x+2) - 4(x - ½)²≤(3x - 5)²- 6(2⅕ x - 2)
3x+2√3x-2√3x-4-4x²+4x-1≤9x²-30x+25-13x+12
7x-5-4x²-9x²+43x-37≤
-13x²+50x-42≤0

Δ=b²-4ac
Δ=2500-2184
Δ=316
√Δ=17,77

x₁=(-b-√Δ)/2a=(-50-17,77)/26= -2,6≤0
x₂=(-b+√Δ)/2a=(-50+17,77)/26= -1,24≤0