Odpowiedzi

2009-12-08T18:30:35+01:00
M(NH4Cl)=53,5g/mol

Cp=Cm*M*100%/d
Cp*d=Cm*M*100%
d=Cm*M*100%/Cp
d=3,54*53,5*100%/18%
d=1052,17g/dm3=1,052g/cm3
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