Odpowiedzi

2009-12-09T18:22:23+01:00
Mmol Al2O3= 2*27+3*16=54+48=102g/mol
(54/102)*100%=53%

Mmol Cu2O= 2*64+16=144g/mol
(128/144)*100%=89%

89%>53%
Cu2O