Odpowiedzi

2009-12-09T21:03:50+01:00
2x²-6x=0
delta= 36
pierw z delty = 6
x1= 0
x2=3
x(x-3)


b) 16-ײ -x²+16 (x-4)(x+4) x+4
--------- = -----------------=-------------------=---------
ײ-4× x(x-4) x(x-4) x







c) 8ײ-4× 4x(2x+1) 2(2x+1) 4x²+2
------------ =---------------=------------------=---------------
2ײ - 10× 2x(x-5) (x-5) x-5














d) 2ײ+7×-6
------------ =------------------------
4ײ-9