Odpowiedzi

2012-11-24T09:38:06+01:00

mCuO=64u+16u=80u

mFe2O3=2*56u+3*16u=112u+48u=160u

mNa2CO3=2*23u+12u+3*16u=46u+12u+48u=106u

mH2SO4=2*1u+32u+4*16u=2u+32u+64u=98u

mCa(OH)2=40u+2*16u+2*1u=40u+32u+2u=74u

mFe2(SO3)3=2*56u+3*32u+9*16u=112u+96u+144u=352u

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