Odpowiedzi

2009-12-11T14:55:52+01:00
Log(3x+4)(x+8)=2
log(3x^2+28x+32)=2
3x^2+28x+32=10^2
3x^2+28x+32-100=0
3x^2+28x-68=0
Δ=28^2-4*3*(-68)=784+816=1600
√Δ=40
x1=-68/6
x2=2