Odpowiedzi

2009-12-11T19:25:18+01:00
F(0)= -2/1= -2
f(1)= (1-2)/(1+1) = -1/2
f(2)= (2-2)/(2+1)=0
f(-2)= (-2-2)/(-2+1)=-4/-1=4
f(-1)= (-1-2)/(-1+1)=-3/0 (nie można dzielić przez zero, brak rozwiązania)
f(√2)= (√2-2)/(√2+1)=[(√2-2)(√2-1)]/(2-1)= 4-3√2
2009-12-11T19:38:16+01:00
F(x)=(x-2)/(x+1)
f(0)=-2/1=-2
f(1)=(1-2)/(1+1)=-½
f(2)=(2-2)/(2+1)=0/3=0
f(-2)=(-2-2)/(-2+1)=-4/(-1)=4
f(-1)=(-1-2)/(-1+1)=-3/0-nie istnieje
f(√2)=(√2-2)/(√2+1)=[(√2-2)(√2-1)]/(2-1)=2-√2-2√2+2= 4-3√2