Odpowiedzi

2009-12-12T17:03:59+01:00
I=120nA = 120*10^-9 A =0,00000012 A
t=1s
e=1,6 * 10^-19 C
I=q/t
q=t*I
q=n*e
n*e=I*t
n=(I*t)/e
n=(0,00000012 A * 1s) / (1,6 * 10^-19 C)
n≈7,489811693 * 10^11 protonów
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