Odpowiedzi

2009-12-12T22:08:00+01:00
1
butanol C4H9OH
M C4H9OH=48+9+16+1=74g/mol
mC=4x12=48g

%C=48/74 x100%=64.86%

2
M C7H16=84+16=100g/mol
m alkoholu=100-12=88
wzór ogolny alkoholu CnH(2n+1)OH
12n+2n+1+16+1=88
14n=70
n=5
mC=5x12=60g
mH=12g
mO=16g
mC : mH : mO = 60 : 12: 16 = 15 : 3 : 4
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