Odpowiedzi

2009-12-13T14:11:49+01:00
Butenu
C4H8+6O2= 4Co2 + 4h20
C4H8+4O2=4CO+4H2O
C4H8+2O2=4C+4H2O
etynu
C2H2+5/2O2=2CO2+H20/*2
C2H2+3/2O2=2CO+H20/*2
C2H2+1/2O2=2C+H20/*2
2c2h2+502=4c02+2h20
2C2H2+3C02=4C0+2H20
2C2H2+2O2=4C+2H20
propanu
C3H8+5O2=3CO2 +4H20
C3H8+7/2O2=3CO+4H20/*2
2C3H8+702=6CO+8H20
C3H8+2O2=3C+4H20

  • Użytkownik Zadane
2009-12-13T14:33:16+01:00
Butenu - C₄H₈
całkowite
C₄H₈ + 6O₂ -> 4CO₂ + 4H₂0
niecałkowite
C₄H₈ + 4O₂ -> 4CO + 4H₂O

etynu - C₂H₂
całkowite
C2H2 + 5/2 O2 ---> 2 CO2 + H20 /*2
2 C2H2 + 5 O2 ---> 4 CO2 + 2 H20
niecałkowite
2 C2H2 + O2 ---> 4 C + 2 H2O

propanu - C3H8
całkowite
C3H8 + 5O2 -> 3CO2 + 4H20
niecałkowite
C3H8 + 2O2 -> 3C + 4H20
2009-12-13T18:43:38+01:00
Butenu
C₄H₈+6O₂= 4CO₂ + 4H₂O
C₄H₈+4O₂=4CO+4H₂O
C₄H₈+2O₂=4C+4H₂O
etynu
2C₂H₂+5O₂=4CO₂+2H₂O
2C₂H₂+3O₂=4CO+2H₂O
2C₂H₂+2O₂=4C+2H₂O

propanu
C₃H₈+5O₂=3CO₂ +4H₂O
2C₃H₈+70₂=6CO+8H₂O
C₃H₈+2O₂=3C+4H²O